Particle 1 and particle 2 have masses of m1 = 1.2 × 10-8 kg and m2 = 5.5 × 10-8 kg, but they carry the same charge q. the two particles accelerate from rest through the same electric potential difference v and enter the same magnetic field, which has a magnitude b. the particles travel perpendicular to the magnetic field on circular paths. the radius of the circular path for particle 1 is r1 = 10 cm. what is the radius (in cm) of the circular path for particle 2?

Explanation:

Particle 1, charge q,

The particle is accelerated thanks to the difference voltage V, the electrical energy becomes kinetic energy:

         1

When the particle enter into the magnetic Field, it feels a centripetal magnetic Force, that is why the particle travel on circular path:

             2

We replace 1 in 2:

             3

Particle 2, charge q,

The particle is accelerated thanks to the difference voltage V, the electrical energy becomes kinetic energy:

         4

When the particle enter into the magnetic Field, it feels a centripetal magnetic Force, that is why the particle travel on circular path:

             5

We replace 4 in 5:

             6

The magnetic Field B, the voltage V, the charge q, are the same for both particles. We can divide 6 with 4 and find the radius for the second particle:

amplitude

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