You want to move a 4- kg bookcase to a different place in the living room. if u push with a force of 65 n and the bookcase accelerates at 0.12 m/s2 what is the coefficient of kinetic friction between the bookcase and the carpet

1.65

Explanation:

The equation of the forces along the horizontal direction is:

(1)

where

F = 65 N is the force applied with the push

is the frictional force

m = 4 kg is the mass

is the acceleration

The force of friction can be written as (2), where

is the coefficient of kinetic friction

R is the normal force exerted by the floor

The equation of forces along the vertical direction is

(3)

since the bookcase is in equilibrium. Substituting (2) and (3) into (1), we find

And solving for ,

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