A219-kg log is pulled up a ramp by means of a rope that is parallel to the surface of the ramp. the ramp is inclined at 35.0° with respect to the horizontal. the coefficient of kinetic friction between the log and the ramp is 0.804, and the log has an acceleration of 0.618 m/s2. find the tension in the rope.

2723.377 N

Explanation:

Tension is the pulling force and also the cause of acceleration.

the equation will be: T = ma + μmgcosx + mgsinx where x is the inclination of ramp, a is the net acceleration and rest all are known.  μ=  coefficient of kinetic friction between the log and the ramp

given: m = 219 kg,  a = 0.618 m/s^2 , μ = 0.804, g = 9.8 and x = 35° so sinx = 0.5735 and cosx = 0.8191

T = (219×0.618) + (0.804×219×9.8×0.8191) + (219×9.8×0.5735) = 135.342 + 1413.393 + 1174.642 = 2723.377 N

so easy. just google the electromagnetic waves and it’ll pop up.