Acat chases a mouse across a 0.65 m high
table. the mouse steps out of the way, and
the cat slides off the table and strikes the floor
2.7 m from the edge of the table
the acceleration of gravity is 9.81 m/s2.
what was the cat's speed when it slid off
the table?
answer in units of m/s.

V = 7.5 m/s

Explanation:

Projectile motion is a two dimensional motion experienced by an object or particle that is subjected near the surface of the Earth and moves along a curved path under the influence of gravity only. The path followed by projectile motion is called projectile path.

As the cat followed the projectile path, and we know that in projectile motion the horizontal component of the velocity remains constant throughout its motion. So there is no acceleration along horizontal path.

Given data :

Height = y = 0.65 m

Horizontal distance = x = 2.7 m

Gravitational acceleration = g = 9.81 m/s²

Velocity when cat slid off the table = V = ?

As the cat slides off horizontally, So there is no vertical component of velocity or vertical component of velocity is zero.

Using 2nd equation of motion

y = 0.5 gt²

0.65 = 0.5*9.8*t²

t² = 0.1326

t = 0.36 s

Velocity when cat slid off the table = V = x / t

V = 2.7 / 0.36

V = 7.5 m/s

mass and volume are the answers you are looking for

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards