Arunner starts jogging with an initial velocity of 0.85 m/s and eventually reaches with a final velocity of 5.2 m/s. this change in velocity occurs over a displacement of 12.0 m. what is his acceleration?

The answer to your question is:      a = 1.1 m/s²

Explanation:

Data

v1 = 0.85 m/s

v2 = 5.2 m/s

displacement = 12.0 m

a = ?

Formula

                v2² = v1² + 2ad

                a = (v2² - v1²) / 2d

Process

              a = (5.2² - 0.85²) / (2)(12)

              a = (27.04 - 0.72) / 24

              a = 26.32 / 24

              a = 1.1 m/s²

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

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explanation: