What is the coefficient of friction of a 20.0-kg box that requires 400 n of force to move across the table at constant velocity?

Explanation:

The coefficient of friction (µ) is the ratio of the frictional force (F) to the normal force (N).

µ =F/N

1. Calculate the normal force

2. Calculate the coefficient of friction

The box is moving at a constant velocity, so the frictional force is equal and opposite to the applied force.

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

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force tends to be low and long diustance masses are high