Part a a uniform solid disk of radius 1.60 m and mass 2.30 kg rolls without slipping to the bottom of an inclined plane. if the angular velocity of the disk is 4.46 rad/s at the bottom, what is the height of the inclined plane?

Height will be 3.8971 m        

Explanation:

We have given that radius of the solid r = 1.60 m

Mass of the solid disk m = 2.30 kg

Angular velocity

Moment of inertia is given by

Transnational Kinetic energy is given by as we know that v =

So

Rotational kinetic energy is given by

Potential energy is given by mgh

According to energy conservation

answer: option c.

explanation:

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