The period of rotation of mercury in hours is 1407.6 hr. given that mereury has a radius of 2.4 x 10^6 m at its equator, what is the linear velocity (in m/s) at venus's surface? (enter the magnitude of the linear velocity at the equator.)

v=2.9578 m/s

Explanation:

t= 1407.6 hr

t = 3600 * 1407.6 = 5067360 s

w = 2π/T

    =2π/5067360

w = 1.24 x 10^-6 rad/s

v = r*w

v = 2.9758 m/s

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the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it