Two particles are moving along the x axis. particle 1 has a mass m1 and a velocity v1 = +4.0 m/s. particle 2 has a mass m2 and a velocity v2 = -6.9 m/s. the velocity of the center of mass of these two particles is zero. in other words, the center of mass of the particles remains stationary, even though each particle is moving. find the ratio m1/m2 of the masses of the particles.

i'm just gonna leave this comment here, so i can get a challange done-

explanation:

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft