Acar of mass 1100 kg that is traveling at 27 m/s starts to slow down and comes to a complete stop in 578 m. what is the magnitude of the average braking force acting on the car?

A car of mass 1100 kg that is traveling at 27 m/s starts to slow down and comes to a complete stop in 578 m, experiences an average braking force of -6.9 × 10² N.

A car is initially moving at 27 m/s (u). After a displacement of 578 m (s) it stops, that is, its final velocity (v) is zero. We can calculate the acceleration (a) of the braking force using the following kinematic equation.

The car of mass (m) 1100 kg experiences an acceleration of -0.63 m/s². We can calculate the associated force (F) using Newton's second law of motion.

A car of mass 1100 kg that is traveling at 27 m/s starts to slow down and comes to a complete stop in 578 m, experiences an average braking force of -6.9 × 10² N.

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A car of mass 1100 kg that is travelling at 27 m/s starts to slow down and comes to a complete stop in 578 m. The magnitude of the average braking force acting on the car is 693 N.

Explanation:

The given car of mass of 1100 kg has been travelling at a speed of 27 m/s and the breaking force was applied. To determine the breaking force, following steps can be undertaken,

Applying the equations of motion, as we know,

As the car comes to rest, final velocity v=0.  Substituting the known value into the third equation of motion as mentioned above, we get,

Then, Deacceleration is

Now to calculate the force,

divide the right side by the left side

0.024÷1.2=0.02 for example

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