A2.0- kg box is moving at constant speed of 2.0 m/s on a frictionless horizontal floor. you apply a horizontal force with a magnitude of 4.0 n to make it stop. how long should you apply this force?

1 second

Explanation:

Impluse is the product of force and time. Specifically the force over a time interval is know as impulse. From the second law of motion we get impulse being equal to the change in momentum.

u = Initial velocity = 2 m/s

v = Final velocity = 0

t = Time taken

F = Force applied = 4 N

Time the force has to be applied is 1 second.

0.863333

86%

hope this

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length