Acar initially at rest accelerates at 10m/s^2. the car’s speed after it has traveled 25 meters is most a.) 0.0m/s b.)10.0m/s c.) 22.0m/s d.) 25.0m/s

A car initially at rest accelerates at 10m/s^2. The car’s speed after it has traveled 25 meters is most nearly C.) 22.0 m/s

Speed: This can be defined as the rate of change of distance. The s.i unit of speed is m/s.

The question above can be solved using the formula below.

v² = u²+2as Equation 1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance.

From the question,

Given: u = 0 m/s ( Initially at rest), a = 10 m/s², s = 25 meters.

Substitute these values into equation 1

v² = 0²+2(10)(25)

v² = 500

v = √(500)

v = 22.36 m/s.

From the question above, the correct option is C.) 22.0 m/s.

Hence the car's speed is C.) 22.0 m/s

Learn more about speed here: link

The car traverses a distance after time according to

where is its acceleration, 10 m/s^2. The time it takes for the car to travel 25 m is

5 is pretty close to 4, so we can approximate the square root of 5 by 2. Then the car's velocity after 2 s of travel is given by

which makes C the most likely answer.

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