A45.0 kg skier testing a new competitive ski wax drops off a ledge, goes into a crouch and goes straight down a slope of 10.0◦ with respect to the horizontal. the coefficient of kinetic friction between the snow and skis is 0.114. the skier’s speed after traveling 300 m along this slope is (in m/s):

v = 21.03 m/s

Explanation:

given,

mass of skier = 45 kg        

the slope of the snow = 10.0◦      

coefficient of friction = 0.114  

distance traveled = 300 m      

speed = ?              

Acceleration = g sin θ - µ g Cos θ        

= 9.8 × Sin (10°) - 0.10 × 9.8 × Cos(10°)        

= 0.737 m/s²      

using equation of motion        

v² = u² + 2 a s        

v² = 0 + 2 × 0.737 × 300            

v = 21.03 m/s                  

Speed of skier's after travelling 300 m speed is  equal to 21.03 m/s

f=ma newton's second law 7x8=56n

elctricity and magnet is conversion to it