An arrow is launched upward with an initial speed of 100 meters per second (m/s). the equations above describe the constant-acceleration motion of the arrow, where v0 is the initial speed of the arrow, v is the speed of the arrow as it is moving up in the air, h is the height of the arrow above the ground, t is the time elapsed since the arrow was projected upward, and g is the acceleration due to gravity (9.8 m/s2).1. what is the maximum height from the ground the arrow will rise to the nearest meter? 2. how long will it take for the arrow to reach its maximum height to the nearest tenth of a second?

d=510.2m

t=10.2s

Explanation:

The formulas for accelerated motion are:

From them we can get .

We have:

And substitute:

We multiply both sides by 2a, and continue:

Being d the displacement , we have

For our exercise, we will write this as:

And taking upwards direction positive and imposing final velocity 0m/s (for maximum height), we have:

For the time we use:

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

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