Sphere 1 with radius r1 has positive charge q. sphere 2 with radius 4.0r1 is far from sphere 1 and initially uncharged. after the separated spheres are connected with a wire thin enough to retain only negligible charge, (a) is potential v1 of sphere 1 greater than, less than, or equal to potential v2 of sphere 2? what fraction of q ends up on (b) sphere 1 and (c) sphere 2? (d) what is the ratio of the final surface charge density of sphere 1 to that of sphere 2? (answer with 2 significant figures.)

power out to power in less than 100%

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

not too sure thinking all accelerations are pointed down

amplitude

hope this