Alowly high diver pushes off horizontally with a speed of 2.82 m/s from the edge of a platform that is 10.0 m above the surface of the water.
(a) at what horizontal distance from the edge of the platform is the diver 0.897 s after pushing off?
(b) at what vertical distance above the surface of the water is the diver just then?
(c) at what horizontal distance from the edge of the platform does the diver strike the water?

The answer to your question is:

a) x = 2.53 m

b) h = 6.05 m

c) x = 4 m

Explanation:

Data

vo = 2.82 m/s

h = 10.0 m

g = 9.81 m/s2

a) Horizontal distance,  t = 0.897 s

x = vot

x = (2.82)(0.897)

x = 2.53 m

b) Vertical distance

h = (1/2)gt²

h = (1/2) (9.81)(0.897)²

h = 3.94 m

height = 10 - 3.95

            = 6.05 m

c)  horizontal distance

t = √2h/g

t = √(2)(10)/ 9.81

t = √20/9.81

t = √2.04

t = 1.42 s

total distance = 1.42 x 2.82

                      = 4 m

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.