The acceleration due to gravity on the moon is about one-sixth its value on earth. if a baseball reaches a height of 67 m when wurth (jaw6696) – ch 2 lt 3/4 – kreft – (61920) 2 thrown upward by someone on the earth, what height would it reach when thrown in the same way on the surface of the moon? answer in units of m.

402m

Explanation:

We can solve this easily by using the free fall formula:

On both cases the final velocity will be 0m/s (maximum height), so we have:

We know that the velocity the person imparts to the ball will be the same either on Earth or on the Moon, so we write for both cases:

Which means

So we get (taking into account that gravity on earth is 6 times gravity on the Moon):

anchor = archer //

well clustered together.

points close on a scatter diagram