An electric flux of 147 n*m^2/c passes through a flat horizontal surface that has an area of 0.824 m^2. the flux is due to a uniform electric field. what is the magnitude of the electric field if the field points 31.6° above the horizontal?

231.16 N/C

Explanation:

Given

Electric Flux

Area(A)

Given Field point above

Therefore angle between Area vector Electric Field =90-31.6=

We know that Flux is given by

E=231.16 N/C

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