Kalea throws a baseball directly upward at time t = 0 at an initial speed of 13.7 m/s. how high h does the ball rise above its release point? ignore air resistance and use g = 9.80 m/s^2.

h = 9.57 seconds

Explanation:

It is given that,

Initial speed of Kalea, u = 13.7 m/s

At maximum height, v = 0

Let t is the time taken by the ball to reach its maximum point. It cane be calculated as :

t = 1.39 s

Let h is the height reached by the ball above its release point. It can be calculated using second equation of motion as :

Here, a = -g

h = 9.57 meters

So, the height attained by the ball above its release point is 9.57 meters. Hence, this is the required solution.

newton's first law of motion

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