An electric point charge of q1 = 7.85 nc is placed at the origin of the real axis. another point charge of q2 = 3.67 nc is placed at a position of p = 2.88 m on the real axis. at which position can a third point charge of q = -3.47 nc be placed so that the net electrostatic force on it is zero? let the sign of q2 be changed from positive to negative. at which position can the point charge q be placed now so that the net electrostatic force on it is zero?

x = 1.71 m

x = - 9.1068 m

Explanation:

from figure 1

[/tex]f_1 = f_2[/tex]

FROM DATA GIVEN

solving for x we get

2.88 -x = 0.68375 x

x = 1.71 m

b) from figure 2

FROM DATA GIVEN

solving for x we get

2.88 +x = 0.68375 x

x = - 9.1068 m

An  atom  (ours, not carroll's) consists of a positively charged  nucleus, surrounded by one or more negatively charged particles called  electrons. the positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral. most of an atom's mass is in its nucleus; the mass of an electron is only 1/1836 the mass of the lightest nucleus, that of hydrogen. although the nucleus is heavy, it is quite small compared with the overall size of an atom. the radius of a typical atom is around 0.1 to 0.25 nanometres (nm), whereas the radius of a nucleus is about 10-6  nm.  *  if an atom were enlarged to the size of the earth, its nucleus would be only 200 feet in diameter and could easily rest inside a small football stadium.read more on -

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