The table below shows data of sprints of animals that traveled 75 meters. at each distance marker, the animals' times were recorded. which animal moves with non-accelerated motion?

time at distance markers
animal 25 meters 50 meters 75 meters
animal 1 3 seconds 4.5 seconds 5 seconds
animal 2 4.5 seconds 5 seconds 5.25 seconds
animal 3 3.5 seconds 7 seconds 10.5 seconds
animal 4 5 seconds 10 seconds 13 seconds
animal 1
animal 2
animal 3
animal 4

Animal 3

Explanation:

In a non-accelerated motion, the velocity is constant. This means that during equal intervals of time, the distance covered is always the same.

In the table, data are reported for equal intervals of distance: 25 m, 50 m, 75 m. This means that an animal moving with non-accelerated motion must cover these distances in equal times.

We can see that this situation occurs for animal 3. In fact:

Time to cover the first 25 m = 3.5 s

Time to cover the second 25 m (50 m -25 m) = 7 s - 3.5 s = 3.5 s

Time to cover the third 25 m (75 m - 50 m) = 10.5 s - 7 s = 3.5 s

For all the other animals this time is not constant, so animal 3 is the only one moving with non-accelerated motion.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s