Aproton in a synchrotron is moving in a circle of radius 1 km and increasing its speed by v(t) = c1 + c2 t 2 , where c1 = 2.0 × 105m/s, c2 = 105m/s3 .
(a) what is the proton’s total acceleration at t = 5.0 s?
(b) at what time does the expression for the velocity become unphysical?

a) 10^6 m/s^2

b) 7.39 s

Explanation:

Hello!

If the velocity is given by:

Then the acceleration is the derivative of the velocity with respect of time:

a)

Therefore the acceleration at t=5.0s is:

b)

The velocity will become unphysical when it equals the velocity of ligth (3x10^8 m/s)

3x10^8 m/s = 2x10^5 m/s + 10^5 m/s^3 t^2

Solving for t:

t^2 = 2998 s^2

t = 7.39 s

you go to your settings preference and in the end youll see sth that says "i want to delete my acc" click on it and u'll acc will be deleted but u have to wait.

momentum of soft ball three times less than baskey ball