A40 kg skier skis directly down a frictionless slope angled at l-0o to the horizontal. assume the skier moves in the negative direction of an x axis along the slope. a wind force with component f, acts on the skier. what is f" if the magnitude of the skier's velocity is (a) constant, (b) increasing at a rate of 1.0 m/s2, and (c) increasing at arate of 2.0 mlsz?

(a) constant. Fx =68,14 N

(b) increasing at a rate of 1.0 m/s2. Fx = 28,14 N

(c) increasing at a rate of 2.0 m/s2. Fx = -11,86 N

Explanation:

In order to solve this situation, it is useful to depict it graphically. in the image we can see drawn the forces that act upon the skier. Once we understand the situation we can proceed and set the equations that model the system. according to Newton’s second law of motion along the negative x axis displayed on the image:

F_x- m*g*cos⁡(80) = -m*a_x → F_x = m*g*cos⁡(80) - m*a_x

Therefore, if we have the scenario where the velocity of the skier is a constant, that means that a_x=0. Replacing on the previous equation, we have:

F_x = 40 kg*9,81 m/s^2 *cos⁡(80) - 40 kg*0 = 68,14 N

In the scenario where the skier’s velocity increases at a rate of 1,0 m/s2, then a_x=1,0 m/s^2 . Replacing on the previous equation, we have:

F_x = 40 kg*9,81 m/s^2 *cos⁡(80) - 40 kg*1,0 m/s^2 = 28,14 N

Finally, in the scenario where the skier’s velocity increases at a rate of 2,0 m/s2, then a_x=2,0 m/s^2 . Replacing on the previous equation, we have:

F_x = 40 kg*9,81 m/s^2 *cos⁡(80) - 40 kg*2,0 m/s^2 = -11,86 N

What this means is that the wind force Fx acts on the opposite direction that the one assumed on the diagram.

Hope everything was clear. If I can help with anything else, let me know. Good day :D

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.