Aflea jumps by exerting a force of 1.07 10-5 n straight down on the ground. a breeze blowing on the flea parallel to the ground exerts a force of 1.12 10-6 n on the flea. find the direction and magnitude (in m/s2) of the acceleration of the flea if its mass is 6.0 10-7 kg. (let us assume that fwind points to the right. we will consider this to be the +x direction and vertical to be the +y direction.) magnitude m/s2 direction ° (measured clockwise from the vertical)

The acceleration will be 18 m/s², 6° from the vertical.

Explanation:

The resulting force will be the sum of both forces (see figure):

F flea = (0, 1.07 × 10⁻⁵ N)

F wind = (1.12 × 10⁻⁶ N, 0)

Resulting force = F flea + F wind

R F = (0, 1.07 × 10⁻⁵ N) +  (1.12 × 10⁻⁶ N, 0) = ( 1.12 × 10⁻⁶ N, 1.07 × 10⁻⁵ N)

The magnitude of the resulting force will be:

The magnitude of the acceleration will be:

F = m·a

Where

F = force

m = mass

a = acceleration

F/m = a

1.08 × 10 ⁻⁵N / 6.0 × 10⁻⁷ kg = 18 m/s²

The direction of the acceleration will be the same as the direction of the resulting force. Using trigonometry:

cos α = adjacent/hypotenuse = 1.12 × 10⁻⁶ N / 1.08 × 10⁻⁵ N

α = 84°

Then the acceleration will be:

18 m/s² (90° - 84°) 6° from the vertical.

area of focus

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.