An irrigation canal has a rectangular cross section. at one point whare the canal is 16.0 m wide, and the water is 3.8 m deep, the water flow is 2.8 cm/s. at a second point downstream, but on the same level, the canal is 16.5 m wide, but the water flows at 11.0 cm/s. how deep in meters is the water at this point?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Because its reliable.   there is no pollution  the chances of a radiation leak is low