Awell hole having a diameter of 5 cm is to be cut into the earth to a depth of 75 m. determine the total work (in joules) required to raise the earth material to the surface if the average mass of 1 m is 1830 kg. (data: g = 9.81 m/s) (hint: how much work is required to raise a volume of ad/4 x dx from a depth of x feet to the surface?

total work is 99.138 kJ

Explanation:

given data

diameter = 5 cm

depth = 75 m

density = 1830 kg/m³

to find out

the total work

solution

we know mass of volume is

volume =

volume =

so

work required to rise the mass to the height of x m

dw = gx dx

so total work is integrate it with 0 to 75

w =

w = × 0.05² × 1830× 9.81×

w = 99138.53 J

so total work is 99.138 kJ

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j