15 points
a car skidded to a stop, leaving tire marks on the road that were 250 m long. if the tires slowed the car down at a rate of -3.5 m/s2, what was the initial velocity of the car?

The given equation tells the relationship between the velocity and the length of skid mark,so simply by putting the given values,we can determine the length of the skid mark.

Given,

v

=

25

miles/ hrs=

25

⋅

(

5280

3600

)

f

t

s

i.e

36.67

f

t

s

f

=

0.5

So,from the equation,we get the length of the skid mark=

d

=

36.67

√

32

⋅

0.5

i.e

12.98

f

tExplanation:

what are the statements? x