Aneutron star has a mass of 2.0 × 1030 kg (about the mass of our sun) and a radius of 5.0 × 103 m (about the height of a good-sized mountain). suppose an object falls from rest near the surface of such a star. how fast would this object be moving after it had fallen a distance of 0.017 m? (assume that the gravitational force is constant over the distance of the fall and that the star is not rotating.)

30298514.82 m/s

Explanation:

M = Mass of star = 2×10³ kg

r = Radius of star = 5×10³ m

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The object would be moving at a velocity of 30298514.82 m/s

Velocity will be

Explanation:

We have given mass of the star

Gravitational constant

We know that acceleration is given by

Displacement is given as s = 0.017 m

From third equation of motion

As initial velocity u = 0 m/sec

So

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15.3 cos 65 degrees trig