The rigid beam bc is supported by rods (1) and (2). the cross-sectional area of rod (1) is 11 mm2. the cross-sectional area of rod (2) is 14 mm2. for a uniformly distributed load of w = 3.9 kn/m, determine the length a so that the normal stress is the same in each rod. assume l = 3.35 m.

la última respuesta, tanto a   y c.

explanation:

could i give you a exaplo that could you?

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s