Physics, 26.09.2019 01:20, ashleymartinez147
The net forward force on the propeller of a 3.2 kg model airplane is 7.0 n. what is the acceleration of the airplanes
Answers: 1
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Let's substitute and solve for whatever is left behind:![7.0N= 3.2kg *a[tex]a =\frac {7.0}{3.2} \frac{N}{kg} = 2.1875 \frac{kg\frac{m}{s^2}}{kg}=2.1875 \frac{m}{s^2}](/tpl/images/0263/1729/276b4.png)
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The net forward force on the propeller of a 3.2 kg model airplane is 7.0 n. what is the acceleration...
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