The plug has a diameter of 30 mm and fits within a rigid sleeve having an inner diameter of 32 mm. both the plug and the sleeve are 50 mm long. determine the axial pressure p that must be applied to the top of the plug to cause it to contact the sides of the sleeve. also, how far must the plug be compressed downward in order to do this? the plug is made from a material for which e = 5 mpa, n = 0.45.

P=740 KPa

Δ=7.4 mm

Explanation:

Given that

Diameter of plunger,d=30 mm

Diameter of sleeve ,D=32 mm

Length .L=50 mm

E= 5 MPa

n=0.45

As we know that

Lateral strain

We know that

So the axial pressure

P=740 KPa

The movement in the sleeve

Δ=7.4 mm

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

small = small current large mag large current