In the daytona 500 auto race, a ford thunderbird and a mercedes benz are moving side by side down a straightaway at 68.0 m/s. the driver of the thunderbird realizes that she must make a pit stop, and she smoothly slows to a stop over a distance of 250 m. she spends 5.00 s in the pit and then accelerates out, reaching her previous speed of 68.0 m/s after a distance of 420 m. at this point how far has the thunderbird fallen behind the mercedes benz, which has continued at a constant speed?

1010 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Time taken by the thunderbird to stop is 7.35 seconds

Time the thunderbird was at the pit is 5 seconds

Time taken to accelerate back to 68 m/s is 12.36 seconds

Total time to this point is 7.35+5+12.36 = 24.71 seconds

The Mercedes Benz is moving at a constant velocity hence it has no acceleration and we use the formula

Distance = Speed × Time

⇒Distance = 68 × 24.71 = 1680 m

The thunderbird has covered 250+420 = 670 m

So, the distance between them is 1680-670 = 1010 m

i think the answer is a, hope this : )