5) a bowling ball is dropped on the jupiter from a height of 3 meters with an initial velocity of 0.4
m/s. the acceleration of gravity on jupiter is 24.5 m/s2. how long does it take for the bowling
ball to reach the surface of jupiter?

0.48 s

Explanation:

The vertical position of the ball at time t is given by:

where

h = 3 m is the initial height

u = 0.4 m/s is the initial velocity

g = 24.5 m/s^2 is the acceleration of gravity on the surface of Jupiter

The negative signs are due to the fact that the direction of the initial velocity and of the acceleration are downward

The ball reaches the surface at time t such that y(t)=0, so:

Substituting values,

Solving the second-order equation, we find:

which gives two solutions:

t = 0.48 s

t = -0.51 s

We discard the second one since it is negative, so the ball reaches the surface after 0.48 s.

a, c, d, e are all applying about success strategies.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards