An object of mass m is sliding with speed vi at some instant across a level tabletop, with which its coefficient of kinetic friction is µ. it then moves through a distance d and comes to rest. which of the following equations for the speed vi is reasonable? vi = v2µdvi = v2µmgdvi = v-2µmgdvi = v-2µgdvi = v2µgd

√2µgd = vi

Explanation:

Given that the mass of object is m

Sliding speed of object is vi

coefficient of kinetic friction is µ

Distance covered is d

Final speed, vf is 0

Equation to apply will be;

v²f=v²i-2µgd where  g is acceleration due to gravity

v²f+2µgd=v²ibut v²f = 0

2µgd=v²i

√2µgd = vi

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

where are the vectors ?