two electric bulbs marked (25 w - 220 v and(100 w - 220 v are connected in series to
a 440 v supply which of the bulbs will fuse
a. 100 w.
6.25 w
c. none of this. d. both.

Ithink it’s 98 because jajajjajansmsmjs

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.