Abeam of electrons with energy 250 me v is elastically scattered through an angle of 10° by a heavy nucleus that is at rest. it is found that the differential cross-section is 65% of that expected for scattering from a point-nucleus. estimate the root mean square radius of the nucleus. neglect the recoil of the nucleus and use the rest mass of the electron as 0.511 mev/c

i think it's 35 meters

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s