Asatellite of mass 5000 kg orbits the earth (mass = 6.0 x 1024 kg) and has a period of 6000 s. in the above problem the altitude of the satellite above the earth's surface is

ht = 776.63 km above earth's surface

Explanation:

Since the satellite is moving in a circular path, we know that:

    Let this be eq1

If now we express the sum of forces on the satellite:

  Replacing the value from eq1 into this equation:

 Solving for R:

  If we subract the earth radius from this value, we'll get the altitude above earth's surface:

ht = 776.63 km

are there answer choices to this question? this seems like a question where you have options to choose from.