Charge q is uniformly distributed on a disk of radius a. (a) evaluate o in terms of q and a. (uniform means not a function of position-variable r! ) (b) evaluate the enclosed charge function q(r) for 0 srce in terms of r and the constants q and ar; graph this function for 0 sr . always check solutions at the limits of a variable's range. here q(r=0) = 0: qr 2 a) = q. charge may lie in points q, or be distributed on lines, on surface sheets, or in volumes, with densities: charge-per-unit-length a = dy/dl; charge-per-unit-area o = dq/da ; or charge-per-unit-volume p = dp/dr. these distributions can be squeezed or stretched into one another, involving mathematical infinities.

Isuck at math i am no sorry

Answertraveling around a circular trackexplanation"traveling around a circular track" is the best answer as you could be traveling around a circular track at a constant speed. your velocity would therefore have the same magnitude but will always be constantly direction. since acceleration is the rate of change of velocity, the rate of change will only involve the direction of velocity and not the magnitude.wrong choices: "an object at rest" does not accelerate at all"increasing speed while traveling around a curve" means that the acceleration will not be constant due to only change in direction; it will be constant due to both magnitude and direction"an object in free fall" does not necessarily change direction 

Answer ( slope);