Athree-wheeled car moving along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 35.0 m/s. then the vehicle moves for 83.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s. (a) how long is the three-wheeled car in motion (in s)? 105.5 s (b) what is the average velocity of the three-wheeled car for the motion described? (enter the magnitude in m/s.) m/s

(a) Total time = 105.5 sec

(b)average speed = 31.26 m/sec

Explanation:

We have given that three-wheeled car starts from rest that initial velocity u = 0 m/sec

Final velocity = 35 m/sec

Acceleration

According to first law of motion we know that v = u+at

So

t = 17.5 sec

After this car travels 83 sec at a constant speed and after that it takes 5 sec additional time to stop

(a) So total time in which car is in motion = 17.5+83+5 = 105.5 sec

(b) Total distance traveled during first 17.5 sec

Distance traveled in 83 sec with with velocity of 35 m/sec =

For next 5 second

Initial velocity u = 35 m/sec

Final velocity = 0 as finally car stops

So

Distance traveled

So total distance traveled = 306.25+2905+87.5 = 3298.75 m

Total time = 105.5 sec

So average speed

b.

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