An object is thrown upward from the top of a 128-foot building with an initial velocity of 112 feet per second. the height h of the object after t seconds is given by the quadratic equation h equals negative 16 t squared plus 112 t plus 128. when will the object hit the ground?

Time, t = 8 seconds

Explanation:

An object is thrown upward from the top of a 128-foot building with an initial velocity of 112 feet per second. The height h as a function of time t is given by :

We need to find the time when the object will hit the ground. When it will hit the ground, h = 0

So,

On solving the above quadratic equation, we get the value of t = 8 seconds. So, after 8 seconds the object will hit the ground. Hence, this is the required solution.

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