The height of an object thrown upward from the floor of a canyon 106 ft deep, with an initial velocity of 120 ft per second, is given by the equation h=-16x^(2)+120x-106, where h represents the height of the object in feet after x second. how long will it take the object to rise to the height of the canyon wall?

Explanation:

The height of an object thrown upward from the floor of a canyon 106 ft deep, with an initial velocity of 120 ft per second. The equation is given by :

Since, the depth of the canyon is (-106 feet) and the time taken by the object to rise to the height of the canyon wall is calculated as :

h = 0

On solving the above quadratic equation,

x₁ = 1.023 seconds

and

x₂ = 6.477 seconds

So, the time taken by the object to rise to the height of the canyon wall is 1.023 seconds (ignoring 6.477 seconds). Hence, this is the required solution.

uranium fissions/breaks up giving out energy and neutrons

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )