11) arthur and betty start walking toward each other when they are 100 m apart. arthur has a speed of 3.0 m/s and betty has a speed of 2.0 m/s. their dog, spot, starts by arthur's side at the same time and runs back and forth between them at 5.0 m/s. by the time arthur and betty meet, what distance has spot run?

C. it comes from the core of the earth.

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.