An object initially at an elevation of 5 m relative to earth’s surface with a velocity of 50 m/s is acted on by an applied force r and moves along a path. its final elevation is 20 m and its velocity is 100 m/s. the acceleration of gravity is 9.81 m/s2 . determine the work done on the object by the applied force, in kj

Explanation:

The work made by the force its equal to the change of mechanical energy

The mechanical energy is given by:

where is the kinetic energy and the potential energy.

We know that, the kinetic energy is

and the potential energy

We can put h=0 at Earth's surface, taking this in consideration, the initial Energy is:

the final Energy is:

The work will be:

As we don't know the mass, we can take the work over mass:

f=gm1m2/d^2 it d

f is force g is gravitaiton constant, m1 is mass of first object, m2 is mass of second object. d is distance between two object

it takes about 30 days for it to break down