Asolid concrete block weighs 140 n and is resting on the ground. its dimensions are 0.370 m x 0.150 m x 0.0820 m. a number of identical blocks are stacked on top of this one. what is the smallest number of whole bricks (including the one on the ground) that can be stacked so that their weight creates a pressure of at least two atmospheres on the ground beneath the first block? (hint: first decide which face of the brick is in contact with the ground.)

18 blocks in total ( 17 add to the original in contact with the ground)

Explanation:

The pressure on the face in contact with the ground ( we choose the face 0.15m x 0.082m)

Pressure= Force ( weigth) /Area

1 Atm = 101325 Pascal [N/ m^2]

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm

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