Aproton with an initial speed of 600,000 m/s is brought to rest by an electric field. part a part complete did the proton move into a region of higher potential or lower potential? because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential. because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential. because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential. because the proton is a positive charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential. previous answers correct here we learn how to determine the distribution of the electric potential based on the movement of a charged particle. part b part complete what was the potential difference that stopped the proton? express your answer with the appropriate units. δv = 1900 v previous answers correct here we learn how to use the law of energy conservation to find the potential difference needed to stop the movement of a charged particle. part c what was the initial kinetic energy of the proton, in electron volts? express your answer in electron volts.