Agirl at an airport rolls a ball north on a moving walking that moves east. if the ball’s speed with respect to the walkway is 0.15m/s and the walkway moves at a speed of 1.50m/s, what is the velocity of the ball relative to the ground?

The velocity of the ball relative to the ground is 1.5m/s at 5.7° North East.

Given the data in the question;

To determine the velocity of the ball relative to the ground.

From Parallelogram law:  

Resultant velocity;

So,

In this case,

We substitute in our values

For the direction

Therefore, the velocity of the ball relative to the ground is 1.5m/s at 5.7° North East.

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We have to add two vectors.

Vector #1: 0.15 m/s north

Vector #2: 1.50 m/s east

Their sum:

Magnitude: √(0.15² + 1.50²)

Magnitude = √(0.0225+2.25)

Magnitude = √2.2725

Magnitude = 1.5075 m/s

Direction = arctan(0.15/1.50) north of east

Direction = 5.71° north of east

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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