The pressure gauge on a tank registers the gauge pressure, which is the difference between the interior pressure and exterior pressure. when the tank is full of oxygen (o2), it contains 14.0 kg of the gas at a gauge pressure of 43.0 atm. determine the mass of oxygen that has been withdrawn from the tank when the pressure reading is 29.4 atm. assume the temperature of the tank remains constant.

9.67 kg

Explanation:

If the gauge pressure is 43 atm, the absolute pressure is 44 atm

p1 = 44 atm = 4.46 MPa

If the gauge pressure is 29.4 atm, the absolute pressure is 30.4 atm

p2 = 30.4 atm = 3.08 MPa

The ideal gas state equation is

p * V = m * R * T

We can set two eqaution for these two times

p1* V1 = m1 * R * T1

p2* V2 = m2 * R * T2

SInce V1 = V2 and T1 = T2

p1 = m1 * R

p2 = m2 * R

Rearranging

R = p1 / m1

R = p2 / m2

Equating:

p1 / m1 = p2 / m2

m2 = m1 * p2 / p1

m2 = 14 * 3.08 / 4.46 = 9.67 kg

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.