The acceleration of a particle traveling along the x axis is given by a(t) = −bt, where b = 7.39 m/s3. in addition, we know that at t = 0, the particle is at the position x0 = 5.00 m and has a velocity of v0 = 10.0 m/s. at the time t = 5.00 s, determine the following for this particle. (indicate the direction with the sign of your answer.)

Answer:

Acceleration of the particle=

Velocity of the particle=

position of the particle=

Explanation:

Given:

t = 0

To find:

The acceleration of particle at t= 5,00 s

Velocity of the particle at t= 5,00 s

Postion of the particle at t= 5,00 s

Solution:

Finding the value of a:

Finding the value of c

Substituting t=0

c=5

Finding the velocity of  of particle at t=5

Position of the particle at x=5

The acceleration of the particle t=5

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation: