A+5.0-μc point charge is placed at the 0 cm mark of a meter stick and a -4.0-μc charge is placed at the 50 cm mark. what is the net electric field at the 30 cm mark? (k = 1/4πε0 = 8.99 × 109 n • m2/c2) a +5.0-μc point charge is placed at the 0 cm mark of a meter stick and a -4.0-μc charge is placed at the 50 cm mark. what is the net electric field at the 30 cm mark? (k = 1/4πε0 = 8.99 × 109 n • m2/c2) 4.0 × 105 n/c 1.4 × 106 n/c 9.0 × 105 n/c 5.0 × 105 n/c

1.4 *10^6 N/C

Explanation:

The electric field caused by a charge at a certain point is given by the equation:

where k is the Coulomb constant equal to 8.99 *10^9 Nm^2/C^2, q the charge of the particle in coulombs, r is the distance from the point to the charge in meters.

is the unitary vector that goes from the charge to the point. This vector will give us the direction of the Electric Field vector.

The unitary vector of the +5.0-μC charge will go to the right (+i), as the point is to the right of the charge. Then, the electric field caused by the charge will be:

The unitary vector of the -4.0-μC charge will go to the left (-i), as the point is to the left of the charge. Then, the electric field caused by the charge will be:

The electric field at the 30 cm mark will be the addition of both electric field:

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz