Physics, 16.09.2019 22:30, hntnhtthnyt

Find the energy (in ev) of a ground state electron in a he ii (he + ) atom. (b.) find the amount of energy (in ev) needed to ionize the ground state electron of part (a). (c.) for which ionization state(s) of carbon could you calculate (principle) quantum energy levels for given the formula for e n presented in class

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answered: xbeatdroperzx

a) -54.42 eV

b) C VI (C +++++)

Explanation:

Hi!

I imagine that the formula given in class is the energy of the hydorgen like atoms, which is:

$E_{n}=-\frac{\text{$\mu $e}^4 Z^2}{32 \pi ^2 n^2 \epsilon _0^2 \hbar }$

Where all are physical constants, such as vacuum permitivity ε0, planck's constant (reduced) h bar, electron's charge e, the atomic number Z, and the reduced mass μ.

The reduced mass is given by the formula:

$\frac{1}{\frac{1}{m_{\text{electron}}}+\frac{1}{m_{\text{nucleous}}}}$

In general the electron's mass is much smaller than the nucleous mass therefore the reduced mass is almost equal to the electron's mass.

If we replace all these constants the energy will become:

$E_{n}=-\frac{Z^{2}13.6 eV}{n^{2} }$

For He --> Z = 2, therefore:

$E_{n}=-\frac{54.42 eV}{n^{2} }$

And the ground state is given when n=1

E = -54.42 eV

This formula applies only to hydorgen like atoms, that is whit only one electron, therefore if an element were to have Z electrons, the formula will only apply to that element ionized Z-1 times.

For C Z=6

We could only calculate the quantum energy levels with the given formula for C VI (C +++++)

answered: Guest

Sorry i don’t know what to do

answered: Guest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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Find the energy (in ev) of a ground state electron in a he ii (he + ) atom. (b.) find the amount of...